Standardwert
0.07
Neon
1.4
Mega Neon
4.5
Nachfrage-Rang
#33
| Variante | Standardwert | Ohne Trank | Fly | Ride | Fly Ride |
|---|---|---|---|---|---|
| Normal | 0.07 | 0.07 | 0.32 | 0.32 | 0.62 |
| Neon | 1.4 | 0.6 | 0.9 | 0.9 | 1.4 |
| Mega Neon | 4.5 | 2.5 | 3.5 | 3.5 | 4.5 |
Das 2025 Birthday Butterfly ist ein uncommon Haustier in Roblox Adopt Me. Sein aktueller Tauschwert beträgt 0.07, mit der Neon-Version im Wert von 1.4 und der Mega Neon-Version im Wert von 4.5. Das 2025 Birthday Butterfly hat einen Nachfrage-Rang von #33 in der Adopt Me Werteliste.
Tauschwerte können je nach Trank-Status variieren. Ein 2025 Birthday Butterfly ohne Trank ist 0.07 wert, während Fly (0.32), Ride (0.32) und Fly Ride (0.62) Versionen jeweils eigene Tauschwerte haben. Nutze unseren Tauschrechner um zu prüfen, ob dein 2025 Birthday Butterfly Tausch fair ist.
In terms of trading value, 2025 Birthday Butterfly is comparable to Persian Cat (0.07) and Lunar Ox (0.07). They sit at nearly identical trading value right now.
Making a Neon 2025 Birthday Butterfly requires 4 full-grown copies combined at the Neon Cave. The Neon version (1.4) is worth 20.0× the regular version — neon crafting is profitable for this pet. A Mega Neon 2025 Birthday Butterfly — requiring 16 total copies — commands a value of 4.5.
The Fly Ride 2025 Birthday Butterfly (0.62) is actually worth more than the No Potion version (0.07), which is common for pets where players value the extra abilities over collector status.
2025 Birthday Butterfly has solid demand (rank #33) among Adopt Me traders. When offering for a 2025 Birthday Butterfly, check the full value table above — potion status can make a significant difference. Fly Ride versions are preferred by most players for this pet.
As a uncommon item in Adopt Me, the value of 2025 Birthday Butterfly is shaped by its availability, demand, and the overall trading market. At demand rank #33, 2025 Birthday Butterfly's value may fluctuate with game updates and seasonal events. Watch our Market Analytics for trend signals.
