
Default Value
3.25
Neon
16
Mega Neon
66
Demand Rank
#78
| Variant | Default Value | No Potion | Fly | Ride | Fly Ride |
|---|---|---|---|---|---|
| Normal | 3.25 | 3.25 | 3.55 | 3.55 | 3.95 |
| Neon | 16 | 15.6 | 15.2 | 15.2 | 16 |
| Mega Neon | 66 | 63 | 64.9 | 64 | 66 |
3.25
20 Jul 25 β 24 Aug 26
All-time high
3.25
All-time low
0.85
Current
3.25
44 recorded prices. The latest point is the current live value.
The Kelp Captain is a legendary pet in Roblox Adopt Me. Its current trading value is 3.25, with the Neon version worth 16 and the Mega Neon version worth 66. The Kelp Captain has a demand rank of #78 in the Adopt Me trading values list.
Trading values can vary based on potion status. A No Potion Kelp Captain is worth 3.25, while Fly (3.55), Ride (3.55), and Fly Ride (3.95) versions each have their own distinct trading values. Use our trade calculator to check if your Kelp Captain trade is fair.
In terms of trading value, Kelp Captain sits close to Purple Butterfly (3.25) and Cerberus (3.25). The two sit at almost identical trading value right now.
Making a Neon Kelp Captain takes four full-grown copies combined at the Neon Cave. The Neon (16) is worth 4.9x the regular version, so crafting one is worth doing rather than buying. A Mega Neon Kelp Captain, which needs sixteen copies in total, is worth 66.
The Fly Ride Kelp Captain (3.95) is worth more than the No Potion version (3.25) β normal for pets where players care more about the abilities than about keeping one untouched.
Kelp Captain sits at demand rank #78, so finding the right trade partner takes more patience. Bundling it with other legendary pets to trade up works well, or look for collectors who specifically want this one. The trade calculator will tell you whether a bundle comes out even.
As a legendary item, Kelp Captain's value comes down to how available it is, how badly people want it, and where the trading market goes. At demand rank #78, Kelp Captain can move with game updates and seasonal events. Market Analytics is where the trend shows up first.