
Default Value
0.09
Neon
1.15
Mega Neon
4.25
Demand Rank
#48
| Variant | Default Value | No Potion | Fly | Ride | Fly Ride |
|---|---|---|---|---|---|
| Normal | 0.09 | 0.09 | 0.29 | 0.29 | 0.54 |
| Neon | 1.15 | 0.6 | 0.88 | 0.88 | 1.15 |
| Mega Neon | 4.25 | 2.6 | 3.43 | 3.43 | 4.25 |
0.09
7 Jan 25 β 9 Sep 26
All-time high
6
All-time low
0.06
Current
0.09
70 recorded prices. The latest point is the current live value.
The Mistletroll is a uncommon pet in Roblox Adopt Me. Its current trading value is 0.09, with the Neon version worth 1.15 and the Mega Neon version worth 4.25. The Mistletroll has a demand rank of #48 in the Adopt Me trading values list.
Trading values can vary based on potion status. A No Potion Mistletroll is worth 0.09, while Fly (0.29), Ride (0.29), and Fly Ride (0.54) versions each have their own distinct trading values. Use our trade calculator to check if your Mistletroll trade is fair.
In terms of trading value, Mistletroll sits close to Ancient Dragon (0.09) and Dragonfly (0.09). The two sit at almost identical trading value right now.
Making a Neon Mistletroll takes four full-grown copies combined at the Neon Cave. The Neon (1.15) is worth 12.8x the regular version, so crafting one is worth doing rather than buying. A Mega Neon Mistletroll, which needs sixteen copies in total, is worth 4.25.
The Fly Ride Mistletroll (0.54) is worth more than the No Potion version (0.09) β normal for pets where players care more about the abilities than about keeping one untouched.
Mistletroll has solid demand at rank #48. Before you offer, check the value table above: potion status changes the number a lot here, and most players want the Fly Ride version of this pet.
As a uncommon pet from the Randoms category, what happens to Mistletroll's value depends largely on whether its egg or event is still obtainable. Retired pets tend to climb over time as fewer copies stay in circulation. At demand rank #48, Mistletroll can move with game updates and seasonal events. Market Analytics is where the trend shows up first.