
Default Value
1.18
Neon
6.75
Mega Neon
28
Demand Rank
#49
| Variant | Default Value | No Potion | Fly | Ride | Fly Ride |
|---|---|---|---|---|---|
| Normal | 1.18 | 1.18 | 1.43 | 1.43 | 1.73 |
| Neon | 6.75 | 5.65 | 6.2 | 6.2 | 6.75 |
| Mega Neon | 28 | 25 | 26.9 | 26 | 28 |
1.18
8 Aug 24 β 24 Aug 26
All-time high
1.18
All-time low
0.3
Current
1.18
77 recorded prices. The latest point is the current live value.
The Snow Monkey is a ultra rare pet in Roblox Adopt Me. Its current trading value is 1.18, with the Neon version worth 6.75 and the Mega Neon version worth 28. The Snow Monkey has a demand rank of #49 in the Adopt Me trading values list.
Trading values can vary based on potion status. A No Potion Snow Monkey is worth 1.18, while Fly (1.43), Ride (1.43), and Fly Ride (1.73) versions each have their own distinct trading values. Use our trade calculator to check if your Snow Monkey trade is fair.
In terms of trading value, Snow Monkey sits close to Prismatic Butterfly (1.2) and Rainbow Dragon (1.15). It trades a little below Prismatic Butterfly right now.
Making a Neon Snow Monkey takes four full-grown copies combined at the Neon Cave. The Neon (6.75) is worth 5.7x the regular version, so crafting one is worth doing rather than buying. A Mega Neon Snow Monkey, which needs sixteen copies in total, is worth 28.
The Fly Ride Snow Monkey (1.73) is worth more than the No Potion version (1.18) β normal for pets where players care more about the abilities than about keeping one untouched.
Snow Monkey has solid demand at rank #49. Before you offer, check the value table above: potion status changes the number a lot here, and most players want the Fly Ride version of this pet.
As a ultra rare pet from the Randoms category, what happens to Snow Monkey's value depends largely on whether its egg or event is still obtainable. Retired pets tend to climb over time as fewer copies stay in circulation. At demand rank #49, Snow Monkey can move with game updates and seasonal events. Market Analytics is where the trend shows up first.